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Integers - DS

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Source: — Data Sufficiency |
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by rijul007 » Wed Dec 14, 2011 1:29 am
For integers a, b, and c; a/(b-c) = 1 , What is the value of (b-c)/b?
(1) a/b = 3/5
(2) a and b have no common factors greater than 1.
a/(b-c) = 1
a = b-c


(b-c)/b
=> a/b

What is the value of a/b?


(1) a/b = 3/5


Sufficient


(2) a and b have no common factors greater than 1.
could be anything
2/3
3/4
4/5
.
.
.

Insufficient

IMO: Option A
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by Anurag@Gurome » Wed Dec 14, 2011 2:09 am
karthikpandian19 wrote:For integers a, b, and c; a/(b-c) = 1 , What is the value of (b-c)/b?
(1) a/b = 3/5
(2) a and b have no common factors greater than 1.
(1) a/b = 3/5
a/(b-c) = 1 or a = b - c
(b - c)/b = 3/5; SUFFICIENT.

(2) a and b have no common factors greater than 1. There can be many such possibilities; NOT sufficient.

The correct answer is A.
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