A set of 15 different integers has a median of 25 and range of 25. what is the greatest possible integer that could be in this set?
a) 32
b) 37
c) 40
d) 43
e) 50
a) 32
b) 37
c) 40
d) 43
e) 50
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Let's tackle this one step at a time.vishal_2804 wrote:A set of 15 different integers has a median of 25 and range of 25. what is the greatest possible integer that could be in this set?
a) 32
b) 37
c) 40
d) 43
e) 50
Median of a set of 15 different integers will be the 8th integer of the series when arranged according to their values.vishal_2804 wrote:A set of 15 different integers has a median of 25 and range of 25. what is the greatest possible integer that could be in this set?
Anju@Gurome wrote:Median of a set of 15 different integers will be the 8th integer of the series when arranged according to their values.vishal_2804 wrote:A set of 15 different integers has a median of 25 and range of 25. what is the greatest possible integer that could be in this set?
Now, Largest - Smallest = Range ---> Largest = (Smallest + Range)
As the range is fixed, we can maximize largest number by maximizing the smallest number.
Maximum possible value of the smallest integer in the set is (25 - 7) = 18, as all the terms are different and 25 is the 8th term.
Hence, greatest possible integer in the set = (18 + Range) = (18 + 25) = 43
The correct answer is D.
Brent@GMATPrepNow wrote:Let's tackle this one step at a time.vishal_2804 wrote:A set of 15 different integers has a median of 25 and range of 25. what is the greatest possible integer that could be in this set?
a) 32
b) 37
c) 40
d) 43
e) 50
First, we have 15 different integers.
We can let these 15 spaces represent the 15 numbers written in ascending order: _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
If the median is 25, we can add this as the middle value: _ _ _ _ _ _ _ 25 _ _ _ _ _ _ _
Notice that 7 of the remaining numbers must be greater than 25 and the other 7 remaining number must be less than 25.
Since, we are told that the range is 25, we know that the greatest number minus the smallest number = 25
Now notice two things:
1) Once we know the value of the smallest number, the value of the greatest number is fixed.
For example, if the smallest number were 10, then the greatest number would have to be 35 in order to have a range of 25
Similarly, if the smallest number were 12, then the greatest number would have to be 37 in order to have a range of 25
2) If we want to maximize the value of the greatest number, we need to maximize the value of the smallest number.
So, how do we maximize the value of the smallest number in the set?
To do this, we must maximize each of the 7 numbers that are less than the median of 25.
Since the 15 numbers are all different, the largest values we can assign to the numbers less than the median of 25 are as follows:
18 19 20 21 22 23 24 25 _ _ _ _ _ _ _ (this maximizes the value of the smallest number)
If 18 is the maximum value we can assign to the smallest number, and if the range of the 15 numbers is 25, then greatest number must equal 43 (since 43 - 18 = 25)
So, the numbers are as follows: 18 19 20 21 22 23 24 25 _ _ _ _ _ _ 43 (the missing numbers don't really matter here)
This means the answer is [spoiler]43 = D[/spoiler]
Cheers,
Brent
In this question we're told that range = 25Gurpreet singh wrote:Hi Brent,
please make me understand this
"If we want to maximize the value of the greatest number, we need to maximize the value of the smallest number"
In a set should not the smallest nos be min possible so that the greatest no is maximum?
Regards
Gurpreet
Typically yes, but remember that here the greatest number can be written as a function of the smallest number:Gurpreet singh wrote:he value of the greatest number, we need to maximize the value of the smallest number"
In a set should not the smallest nos be min possible so that the greatest no is maximum?
Regards
Gurpreet
vishal_2804 wrote:A set of 15 different integers has a median of 25 and range of 25. what is the greatest possible integer that could be in this set?
a) 32
b) 37
c) 40
d) 43
e) 50



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