BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Ages:

Expert replies
by \'manpreet singh » Thu Aug 22, 2013 11:38 pm
Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?
51
52
53
54
55

I want to know a faster approach to solve such a problem.?
Whats the steps that i need to start with such a age problem involving 4 variables.
Join the discussion
Source: — Problem Solving |

by [email protected] » Thu Aug 22, 2013 11:48 pm
Hi manpreet singh,

The first part of this question requires translating sentences into formulas:

J + 2 = K
L + 3 = K
J + 1 = M

Even if you translated these formulas differently, you still have a relationship among the 4 variables that needs to be discovered. TEST the variables to figure out the relationship:

If K = 10, then
J = 8
L = 7
M = 9

Now we know that the 4 values are consecutive.

To solve, you can either use "brute-force" (since the answers are small) or algebra:

Brute-Force:
11 + 12 + 13 + 14 = 50 NOT ENOUGH BASED ON THE ANSWERS
12 + 13 + 14 + 15 = 54 WINNER

Algebra:
Call the youngest person X
X + (X+1) + (X+2) + (X+3) = 4X + 6
If X = 11, total = 50 NOT ENOUGH BASED ON THE ANSWERS
If X = 12, total = 54 WINNER

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by GMATGuruNY » Fri Aug 23, 2013 2:24 am
Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?

· 51
· 52
· 53
· 54
· 55
The ages are all close together.
The answer choices imply that the sum of the 4 ages is between 51 and 55, inclusive.
Since 52/4 = 13, the average age must be around 13.

Let J=13.
Since Joan is 2 years younger than Kylie, K=15.
Since Kylie is 3 years older than Lillian, L=12.
Since Miriam is 1 year older than Joan, M=14.
Sum = 13+15+12+14 = 54.

The correct answer is D.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by faraz_jeddah » Fri Aug 23, 2013 4:59 am
If you are not sure what values to Test, Heres my approach. Let me know what you think of it.

What we need to find is
Total (T) = J+K+L+M

Given:
J = K - 2 _____________ (1)
K = L + 3 _____________ (2)
M = J + 1 _____________ (3)

Adding (1) (2) (3)

J + K + M = J + L + K +2

==> M-L = 2
OR M = L+2 ____________ (4)

Also,
From (1) and (2)
J = L + 1 _______________ (5)

Now back to the question

T = J + K + L + M

Substitute (4)

T = J + K + L + L + 2
= J + K + 2L + 2

Substitute (2) and (5)

= L + 1 + L + 3 + 2L + 2
T = 4L + 6

This shows you that that total age should be a multiple of 4 plus 6

Of the answer choices only 54 fits i,e 4(12) + 6

Answer is D
[spoiler][/spoiler]
A good question also deserves a Thanks.

Messenger Boy: The Thesselonian you're fighting... he's the biggest man i've ever seen. I wouldn't want to fight him.
Achilles: That's why no-one will remember your name.
Join the discussion

by ganeshrkamath » Fri Aug 23, 2013 5:32 am
'manpreet singh wrote:Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?
51
52
53
54
55

I want to know a faster approach to solve such a problem.?
Whats the steps that i need to start with such a age problem involving 4 variables.
Let J,K,L,M represent the ages of Joan, Kylie, Lillian, Miriam respectively.
J = K-2
K = L+3
M = J+1
L seems to be the youngest.
So write everyone's age in terms of L.
K = L+3
J = L+1
M = L+2
So sum of ages = L + L+3 + L+1 + L+2
= 4L + 6
So sum is an even number.
Eliminate A,C,E.
Option B = 52 = 4L + 6
L = 46/4 which is not an integer (all celebrate their birthday today. So every age should be an integer)
Eliminate B.

Choose D

Cheers
Every job is a self-portrait of the person who did it. Autograph your work with excellence.

Kelley School of Business (Class of 2016)
GMAT Score: 750 V40 Q51 AWA 5 IR 8
https://www.beatthegmat.com/first-attemp ... tml#688494
Join the discussion

by Brent@GMATPrepNow » Fri Aug 23, 2013 5:33 am
manpreet singh wrote:Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?
A) 51
B) 52
C) 53
D) 54
E) 55
We can solve the question using 1 variable.

Let's let Joan's age = J (aside: we could assign the initial variable to someone else's age, but at first glance Joan appears to be one of the younger people, and it's often easier to assign the first variable to the smallest/smaller value)

Joan is 2 years younger than Kylie: So, Kylie's age = J+2
Kylie is 3 years older than Lillian: In other words, Lillian's age is 3 years less than Kylie's age. So, Lillian's age = (J+2)-3 = J-1
Miriam is one year older than Joan: So, Miriam's age = J+1

The sum of all 4 ages = J + (J+2) + (J-1) + (J+1) = 4J+2

IMPORTANT: The sum of the ages is 2 more than some multiple of 4.
Scan the answer choices.
52 is a multiple of 4.
So, 54 is 2 more than some multiple of 4
Answer = D

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by ani781 » Sat Aug 24, 2013 6:49 am
I approached this problem in the following way :
Let L = x ;
=> K = x+3 ; J = (x+3)-2 ; M = x+2.

So, adding them, 4x + 6 = 2(2x+3) is the sum.

So we can eliminate 51, 53 & 55.

52/2 = 26 , not possible ( as 2x+3 is Odd). So correct answer is 54.
Join the discussion