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x and y are integers and x>0 is y>0?

Expert replies
Source: — Data Sufficiency |

by niraj_a » Thu Aug 27, 2009 9:49 am
A?

tried it without pen and paper so lets see if i have BETTER accuracy. lol
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by pradeepsarathy » Thu Aug 27, 2009 9:51 am
IMO E

Stmt 1 -
7x-2y>0

=> 7x>2y
=>y<7x/2
plug a value : say x=2, since x>0
=>y<7
=>y can be either positive or negative
Hence Insufficient

Stmt 2 -
-y<x
=> y > -x
Plug values : x = 2, since x>0
=>y > -2
=>y can be either positive or negative
Hence Insufficient

Stmt 1 and Stmt 2 -
7x/2 > y > -x

Plug values : x = 2, since x>0
=>7 > y > -2
=>y can be either positive or negative
Hence Insufficient

Note: The reason I took x=2 as the only VIC is because, all we care is to prove that the stmts are insufficient.Had the value x=2 satisfied any of these two stmts, then we should try with different values for 'x' to figure out the solution.
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by ogbeni » Thu Aug 27, 2009 10:50 am
Thanks!!
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by m&m » Thu Aug 27, 2009 12:06 pm
in 1
7x>2y
3.5x>y

can be either neg or pos

in 2
0<x+y

again y<x but positive or negative

if combine both then
intersect can be neg or positive. Example y=1 or -1 and x=100

so E
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by [email protected] » Tue Oct 02, 2012 12:46 pm
I am trying to solve this graphically and I get D. Can someone help me here? Thank you.
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