The correct answer is definitely choice B, and this is yet another weighted average problem.
From the stem, 72% of the males, and 80% of the females applied to college. The second statement tells us that, overall, 75% of them applied to college.
Question. What if, overall, 76% applied to college? Because 76 is 4 units away from 72, and also 4 units away from 80, wouldn't it then be clear that half are males and half are females?
In the question, we have:
72...75.....80
(M)...........(F)
Because the overall average is only 3 units away from 72 (the males), but 5 units away from 80 (the females), there are clearly more males. In fact, the males to female proportion is exactly 5:3. Therefore, the male to total ratio is 5:8, and the second statement is sufficient by itself. (Because the overall average is closer to the male average, there must be more males "weighting" the average).
You can take this as a general takeaway. Let's call the grand average MEAN. If X is x units away from MEAN, and Y is y units away from MEAN, then the proportion X/Y is just y/x.
And because this is DS, you don't even need to compute the 5:8 ratio; instead, you just need to realize that you COULD compute the appropriate ratio.
Kaplan Teacher in Toronto