x^1/2=2k (where k is integer)PAB2706 wrote: 1) x^1/2 is a multiple of 2
hence
x= 4(k)^2 = even integer
x^2 = 4k2) x^2 is a multiple of 4
x=+2(k)^1/2
or
x=-2(k)^1/2
here k^1/2 may or may not be an integer depending upon k's value
Is x an even integer?
This topic has expert replies
Source: Beat The GMAT — Data Sufficiency |
My ans is A
hence
x= 4(k)^2 = even integer
x=+2(k)^1/2
or
x=-2(k)^1/2
here k^1/2 may or may not be an integer depending upon k's value
hence
x= 4(k)^2 = even integer
x=+2(k)^1/2
or
x=-2(k)^1/2
here k^1/2 may or may not be an integer depending upon k's value
Kid in Verbal 
