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Geometry

by vinni.k » Wed Oct 03, 2012 9:26 am
The symbol for a particular company is a circle, but to commemorate a certain event, a decorative square is being added to the center of the circle. If the original symbol in front of the company's headquarters has a diameter of 6 feet, what is the largest side length the square can have while still being completely confined within the circle?

(A). √π/3
(B). 9√π
(C). 3
(D). 3√2
(E). 6

Answer is D

Thanks & Regards
Vinni
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by anuprajan5 » Wed Oct 03, 2012 9:41 am
I solve this by POE.

If the diameter is 6 feet, then the area is 9pi which is roughly close to 28 sqft.

Taking the sides and calculating area

(A). √π/3 - pi/9 - less than 1/3 - Eliminate
(B). 9√π - 81* pi = 243 > 28 - Eliminate
(C). 3 - 9 - Eliminate
(D). 3√2 - 18 - Keep
(E). 6 - 36 - Eliminate

Choice D

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by das.ashmita » Wed Oct 03, 2012 11:33 am
Hi vinni


Image

Simple approach:
The diagonal(d) of the square (largest size) must be equal to the diameter of the circle.
therefore side of square = d /root(2) = 6/root(2) = 3root(2)

ANS D

Hope its clear :)

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by vinni.k » Thu Oct 04, 2012 6:53 am
Thanks Guys. Appreciate your help.

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Vinni

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by Javoni » Fri Oct 05, 2012 10:25 pm
Here we go,

Since the question stem asks for the largest side that our imaginary square could have, the diagonal of the square at issue must be the diameter of the circle set forth in the problem. Hence, according to the Pythagorean proposition we got a^2+a^2 = d^2, here a - is side of our square and d - is diameter of the circle. Consequently, 2a^2 = 36 ---->>>>>> a = 3*(a)^0.5 or (D)

vinni.k wrote:The symbol for a particular company is a circle, but to commemorate a certain event, a decorative square is being added to the center of the circle. If the original symbol in front of the company's headquarters has a diameter of 6 feet, what is the largest side length the square can have while still being completely confined within the circle?

(A). √π/3
(B). 9√π
(C). 3
(D). 3√2
(E). 6

Answer is D

Thanks & Regards
Vinni
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