BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

DATA SUFFICIENCY

Expert replies
Source: — Problem Solving |

by Mike@Magoosh » Tue Mar 27, 2012 12:31 pm
I'm happy to help with this. :)

Prompt: Is the smallest of nine consecutive integers an even number?

So, we have nine consecutive integers, and we want to know the starting point.

Statement #1: The product of the integers is even.

This is not so helpful. You see, no matter how many odds you multiply together, all you need is one even number, and the whole product is even. Here, if we have consecutive integers, every other one will be even, so we will have plenty of even numbers in the product, so the product will definitely be even, regardless of the starting point. This is completely useless for answering the prompt. Statement #1, by itself, is insufficient.

Statement #2: The sum of the integers is zero.

This is interesting. In order to have a sum of zeros, the string of consecutive numbers must be symmetrically arranged around zero, so there are an equal number of positive and negatives. That means the series of consecutive numbers has to be

-4, -3, -2, -1, 0, 1, 2, 3, 4

We know the series, so we can see that the smallest, -4, is even. We can give a definitive answer to the prompt. Statement #2, by itself, is sufficient.

Answer = B

Here's another DS about consecutive integers:
https://gmat.magoosh.com/questions/943
When you submit your answer, the next page will have a complete video explanation. At Magoosh, we have 800+ GMAT questions, each with its own video explanation. We also have 200+ lesson videos, including lessons on strategies for DS questions like this one. We have a sale ending Thursday, so now's a particularly good time to check us out.

Does all this make sense? Let me know if you have any questions?

Mike :)
Magoosh GMAT Instructor
https://gmat.magoosh.com/
Join the discussion

by ronnie1985 » Wed Mar 28, 2012 10:31 am
(B) is answer

Statement 1 says that the product is even which is true for any 2 consecutive numbers hence insufficient

Statement 2 says that the sum of the integers is zero. Here please note that the median of the numbers is 0 and the starting number must be odd, not even, hence sufficient
Follow your passion, Success as perceived by others shall follow you
Join the discussion