vinay1983 wrote:How many more positive integral factors does 2n have than the positive integer n?
1. n is an odd number
2. n is an odd prime number
Statement 1:
If n=1 (which has only 1 factor), then 2n = 2 (which has factors 1 and 2, for a total of 2 factors).
In this case, the difference between the number of factors = 2-1 = 1.
If n=3 (which has factors 1 and 3, for a total of 2 factors), then 2n=6 (which has factors 1, 2, 3, and 6, for a total of 4 factors).
In this case, the difference between the number of factors = 4-2 = 2.
INSUFFICIENT.
Statement 2:
If n=3 (which has factors 1 and 3, for a total of 2 factors), then 2n=6 (which has factors 1, 2, 3, and 6, for a total of 4 factors).
In this case, the difference between the number of factors = 4-2 = 2.
If n=5 (which has factors 1 and 5, for a total of 2 factors), then 2n=10 (which has factors 1, 2, 5, and 10, for a total of 4 factors).
In this case, the difference between the number of factors = 4-2 = 2.
The cases above illustrate that the difference in every case will be 2.
SUFFICIENT.
The correct answer is
B.
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