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In the xy-plane

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by yangliu0401 » Thu Feb 12, 2009 1:08 pm
In the xy-plane, the point (-2, -3) is the center of a circle. The point (-2, 1) lies inside the circle and the point (4, -3) lies outside the circle. If the radius r of the circle is an integer, then r =

A. 6
B. 5
C. 4
D. 3
E. 2

The ans. is B, but why not C? :roll:
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Re: In the xy-plane

by x2suresh » Thu Feb 12, 2009 1:23 pm
yangliu0401 wrote:In the xy-plane, the point (-2, -3) is the center of a circle. The point (-2, 1) lies inside the circle and the point (4, -3) lies outside the circle. If the radius r of the circle is an integer, then r =

A. 6
B. 5
C. 4
D. 3
E. 2
distance between (-2, 1) (Center) to (-2, -3)
= 4 .. radius >4

distance between (-2, 1) (Center) to (4, -3)
= 6 radius <6

5 is the answer.

B
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by awesomeusername » Thu Feb 12, 2009 1:59 pm
IMO, the point tangent to the circle is not considered to be "inside" the circle. Thus, it must be GREATER THAN 4, but LESS THAN 6.
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