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Ms. Crabtree brought 30 identical pieces

Expert replies
by saxenashobhit » Thu Jul 07, 2011 5:24 am
Ms. Crabtree brought 30 identical pieces of candy to pass out to her kindergarten class. Every student will get the same number of pieces of candy, with no candy left over. Assuming that each piece of candy cannot be divided, how many pieces will each student receive?

1) If her class size were to double, Ms. Crabtree would not have enough candy for each student.
2) If half the class were absent, each student would receive two times as much candy.

Statement (1) BY ITSELF is sufficient to answer the question, but statement (2) by itself is not.

Statement (2) BY ITSELF is sufficient to answer the question, but statement (1) by itself is not.

Statements (1) and (2) TAKEN TOGETHER are sufficient to answer the question, even though NEITHER statement BY ITSELF is sufficient.

EITHER statement BY ITSELF is sufficient to answer the question.

Statements (1) and (2) TAKEN TOGETHER are NOT sufficient to answer the question, requiring more data pertaining to the problem.

Kaplan question 14 - https://www.scribd.com/doc/58999877/GMAT ... et-6-Quant
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Source: — Data Sufficiency |

by Frankenstein » Thu Jul 07, 2011 6:20 am
Hi,
Factors of 30 - 1,2,3,5,6,10,15,30
From(1):
Ms. Crabtree would not have enough candy for each student. - I assume this means that 30 candy pieces cannot be uniformly divided.
The class size,n can be can be any factor of 30 such that 2n is not a factor of 30
n can be 2,6,10,30
So, each of them can receive 15 or 5 or 3 or 1
From(2):
n can be any even factor of 30
n can be 2,6,10,30
So, each of them can receive 15 or 5 or 3 or 1
Both (1) and (2):
n can be 2,6,10,30
So, each of them can receive 15 or 5 or 3 or 1

Hence, E
Cheers!

Things are not what they appear to be... nor are they otherwise
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by newgmattest » Thu Jul 07, 2011 10:49 pm
Hi GMAT Experts,

Please help.

Thanks.
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by amit2k9 » Fri Jul 08, 2011 2:13 am
let t be the number of students then each student will have 30/t pieces.

a 30/2*t < 1. thus t can be > 15. not sufficient.

b 30/(0.5*t) = 2*[30/t]

does not solve for t as t gets cancelled. Hence not sufficient.

a+b
not sufficient as from a t can have values > 15.

hence E it is.
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by dodgeforgmat » Fri Jul 08, 2011 2:37 am
Using the post above by Amit

let t be the number of students then each student will have 30/t pieces.

a 30/2*t < 1. thus t can be > 15.
based on the above and the fact that everystudent gets equal number of candies the only possible number of students t is 30. Hence every student gets 1 candy.
SUFFICIENT

b 30/(t/2) = 2k where k is the original number of candies.
cant solve for t or k hence INSUFFICIENT.

IMO A
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