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If \(r\) and \(s\) are positive, the value of \(\dfrac{2r+3s}{r+s}\) is

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Re: If \(r\) and \(s\) are positive, the value of \(\dfrac{2r+3s}{r+s}\) is

by deloitte247 » Sun Dec 13, 2020 6:27 am
$$\frac{2r+35}{r+5}=\frac{2r}{r+s}+\frac{3s}{r+s}$$
$$=>\frac{2r+2s}{r+s}+5$$
$$=>\frac{2r+2s}{r+s}+\frac{5}{r+s}$$
$$=>\frac{2\left(r+s\right)}{r+s}+\frac{5}{r+s}$$
$$2+\frac{5}{r+s}$$
$$Since\ r\ and\ s\ are\ positive,$$
$$definitely;\ \left(r+s\right)>5$$
$$so\ \frac{5}{\left(r+s\right)}=>a\ fraction\ less\ than\ 1$$
$$0.1\le\left(\frac{s}{r+s}\right)\le0.9$$
$$value\ of\ 2+\frac{s}{r+s}=>\ 2.1\le\frac{2r+3s}{r+s}\le2.9$$
$$Answer\ =\ between\ 2\ and\ 3$$
$$Answer\ =\ C$$
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