Don't force

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Don't force

by sanju09 » Mon Sep 13, 2010 4:00 am
For which of the following functions is f (x) = f (1 - x) for all x?
(A) f (x) = 1 - x
(B) f (x) = 1 - x^2
(C) f (x) = x^2 - (1 - x) ^2
(D) f (x) = x^2 (1 - x) ^2
(E) f (x) = x/ (1 - x)


[spoiler]Source: Don't force[/spoiler]
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by Rahul@gurome » Mon Sep 13, 2010 4:17 am
Best approach is to start from the last choice. So, start from option (E).
(E) f(1 - x) = (1 - x)/[1 - (1 - x)] = (1 - x)/x, which is not equal to f(x).

(D) f(1 - x) = (1 - x)^2 * [1 - (1 - x)]^2 = (1 - x)^2*(x^2), which is the same as f(x).

The correct answer is [spoiler](D)[/spoiler].
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by alivapriyada » Mon Sep 13, 2010 4:28 am
For which of the following functions is f (x) = f (1 - x) for all x?
(A) f (x) = 1 - x
(B) f (x) = 1 - x^2
(C) f (x) = x^2 - (1 - x) ^2
(D) f (x) = x^2 (1 - x) ^2
(E) f (x) = x/ (1 - x)
The same question i got in my prep. And even I answered it correctly in the exam.

Lets start from answer option A
F(x)= 1-x
F(1-x) = 1-(1-x) =-x
eliminate A

come to B
F(x)=1-x^2
F(1-x)= 1-(1-x)^2 =1-(1+x^2-2x)
seems complicated?? we can eliminate this option.

come to C
F(x)=x^2-(1-x)^2
F(1-x)=(1-x)^2-(1-1+x)^2
=(1-x)^2-X^2
not equal
Eliminate C

come to D
F(x)=x^2(1-x)^2
F(1-x)=(1-x)^2 (1-1+x)^2
=(1-x)^2(x)^2
where F(x)=F(1-x)
hence the answer is D