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Probs solving!!!!!!!

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by tpr-becky » Tue May 04, 2010 11:18 am
This is an exponent problem - the crux of the problem is that when you have two different bases with the same exponent you can multiply the bases together and keep the same exponent (this comes from the fact that exponents are just repeated multiplication.) Thus 2^2*3^2=2*2*3*3 which equals 6^2.

So (1/4)^18= (1/2)36. since your answer has a 1/2 muliplied in already you need to get rid of one of these so that becomes 1/5^m*1/2^35=1/10^35 - in order to apply the topic from above you need m to be 35.

Hope that helps.
Becky
Master GMAT Instructor
The Princeton Review
Irvine, CA
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by clock60 » Tue May 04, 2010 11:18 am
mayur c wrote:(1/5)raised to m *(1/4)raised to 18 = 1/2(10)raised to 35,then m =

Plz help me in the solution.

hw can the ans be 35?
is it possible to clarify right part ot the problem
is it ((1/2)^10)^35
or it is (1/2)*10^35
or any other version???
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by harshavardhanc » Tue May 04, 2010 11:23 am
mayur c wrote:(1/5)raised to m *(1/4)raised to 18 = 1/2(10)raised to 35,then m =

Plz help me in the solution.

hw can the ans be 35?
I think the question is :

(1/5)^m * (1/4)^18 = (1/2) * (1/10)^35

RHS : 2^-1 * (2*5)^-35

= 2^-36 * 5^-35

LHS : 5^-m * 2^-36


equating both sides, we get m = 35
Regards,
Harsha
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by clock60 » Tue May 04, 2010 11:33 am
with corrected version it has perfect sence
(1/5)^m*(1/2)^36=(1/2)*(1/2)^35*(1/5)^35
get rid of 1/2 and left
(1/5)^m*(1/2)^35=(1/2)^35*(1/5)^35
now we can cancel 1/2^35 from both parts and left with
(1/5)^m=(1/5)^35
m=35
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