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Triangles in a heptagon

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by rahulvsd » Mon Mar 05, 2012 6:46 am
How many triangles can be inscribed in the heptagon pictured, where the three vertices of the triangle are also vertices of the heptagon?

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A.9 B. 21 C. 35 D. 140 E. 210.

[spoiler]Ans: C. Grockit solves this by using combinations method and I agree with this solution. If the question mentions non-overlapping triangle, will the answer be 5. By using formula (n-2) *180, so here it will be 5 * 180 so 5 triangles, is this approach correct? And if the question was rephrased as number of triangles (does not mention non - overlapping) in a hexagon by the combination method answer will be 6 factorial / 3 factorial * 3 factorial. So 20 triangles, is this correct too? please confirm... [/spoiler]
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Source: — Problem Solving |

by pemdas » Mon Mar 05, 2012 10:58 am
i selected this option --> one vertice needs two more vertices to form triangle and in total three vertices will be required out of seven, 7C3=35

c
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by Jim@StratusPrep » Mon Mar 05, 2012 11:14 am
35 is the answer: 7*6*5/3!
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by Scott@TargetTestPrep » Thu Jan 17, 2019 5:47 pm
rahulvsd wrote:How many triangles can be inscribed in the heptagon pictured, where the three vertices of the triangle are also vertices of the heptagon?

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A.9 B. 21 C. 35 D. 140 E. 210.
Since there are 7 vertices on the heptagon and any of its 3 vertices will form a triangle, then the number of possible triangles is 7C3 = 7!/(3! x 4!) = (7 x 6 x 5)/3! = (7 x 6 x 5)/(3 x 2) = 35.

Answer: C

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