Mo2men wrote:Of 120 hotel rooms rented one night, some were suites rented for $115 each and the rest were double rooms rented for $85 each. If the total revenue from the room rentals for this night was $10,890, how many suites were rented?
A) 23
B) 35
C) 54
D) 94
E) 99
We can solve this equation using 1 variable or 2 variables.
Let's use 1 variable.
Let
x = # of suites rented
Since 120 rooms were rented in total,
120-x = # of double rooms rented
Suites rented for $115 each
So, revenue from the
x suites = 115
x
Double rooms rented for $85 each
So, revenue from the
120-x double rooms = 85(
120-x)
TOTAL revenue was $10,890
So, 115
x + 85(
120-x) = 10,890
Expand to get: 115x + 10,200 - 85x = 10,890
Simplify left side: 30x + 10,200 = 10,890
Subtract 10,200 from both sides to get: 30x = 690
Divide both sides by 30 to get: x = 23
Answer:
A
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
