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jimmy.student
- Newbie | Next Rank: 10 Posts
- Posts: 3
- Joined: Wed Dec 15, 2010 3:57 am
hmhm
this question was discussed so many times before.
suppose I is the center of the circle
triangle PIR has IRP^=RPI6=35 so PIR^=110
PI)^=70
triang OPI=triange RQI because PQ// OR > OP=PQ, IO=Ir and PI=QI
so PIO^=70 => PIQ=40
40/360*18p=2p













