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If \(k\) is an integer and \(\dfrac{33!}{22!}\) is divisible by \(6k,\) what is the maximum possible value of \(k?\)

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If \(k\) is an integer and \(\dfrac{33!}{22!}\) is divisible by \(6k,\) what is the maximum possible value of \(k?\)

by Gmat_mission » Sun Dec 26, 2021 10:54 am

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If \(k\) is an integer and \(\dfrac{33!}{22!}\) is divisible by \(6k,\) what is the maximum possible value of \(k?\)

(A) 3
(B) 4
(C) 5
(D) 6
(E) 7

Answer: D

Source: Manhattan GMAT
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