GmatKiss wrote:If m, p, and t are positive integers and m<p<t, is the product mpt an even integer?
(1) t - p = p - m
(2) t - m = 16
[spoiler]IMO:A[/spoiler]
For mpt to be odd, all 3 values (m, p and t) must be odd.
Question rephrased: Are m, p and t all odd?
Statement 1: t-p = p-m.
m+t = 2p
p = (m+t)/2.
The implication is that p is HALFWAY between m and t.
Thus, all 3 values could be even (2,4,6), or all 3 values could be odd (1,3,5).
INSUFFICIENT.
Statement 2: t = m+16.
If m=1, then t=17.
If p=9 , then all 3 values are odd.
If p=10, then all 3 values are not odd.
INSUFFICIENT.
Statements 1 and 2 combined:
To satisfy both statements, t = m+16, and p is halfway between m and t.
If m=1 and t=17, then p=9, in which case all 3 values are odd.
If m=2 and t=18, then p=10, in which case all 3 values are not odd.
INSUFFICIENT.
The correct answer is
E.
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