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by resilient » Tue Mar 04, 2008 2:58 pm
3 digit number yields a remainder of 1 when it is divided by both 100 and 60. How many 3 digit numbers are there with this property?

none
one
two
three
four

qa is three


100: 101,201,301.......901
60: 300,600,900

THEREFORE QA IS THREE.

i DONT SEE HOW HOW BOTH 100 AND 600 GIVE A REMAINDER OF 1 WITH 300, 600 AD 900. WHAT AM I NOT SEEING?
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by Stuart@KaplanGMAT » Tue Mar 04, 2008 3:26 pm
The question is really asking us to find 3 digit common multiples of both 60 and 100 and then add 1 to them.

Since 100 is the bigger number, let's look at multiples of 100:

100
200
300
400
500
600
700
800
900

Next let's pick numbers already on our list that are also multiples of 60:

300
600
900

So, the 3 digit numbers that will yield a remainder of 1 when divided by both 60 and 100 are:

301
601
901
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weakness

by resilient » Tue Mar 04, 2008 5:10 pm
I can understand the math and underlying concepts fully. I often get tripped by the language and not actually understanding the question. Do you have a remedy?
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