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N=2^j*3^k

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by outreach » Tue Jul 20, 2010 11:40 am
N=2^j*3^k, where j and k are positive integers. what is the value of N
a. 2 is divisor of N , but 4 is not
b. N is divisor of 36 but not 24

OA : C
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Source: — Data Sufficiency |
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by Patrick_GMATFix » Tue Jul 20, 2010 11:53 am
The value of N depends on the values of j and k.

(1) 2 is a factor of n, but 2^2 is not. This means that j=1. We still don't know k. NOT SUFFICIENT

(2) N is divisor of 36 means N is part of the set {1,2,3,4,6,9,12,18,36}. Since N is not a divisor of 24, N cannot be 1,2,3,4,6 or 12. So this statement tells us that N is part of the set {9,18,36}. This gives us three possible solutions but not the exact value of N. NOT SUFFICIENT

Merge statements. we know that N cannot be 36 since 4 is not a factor of N. Furthermore, we know that 2 is a divisor of n (meaning N is even). So the set of possible values we derived from statement 2 (N={9,18,36}) is reduced to N=18.

Pick C

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