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Source: — Problem Solving |
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by cans » Mon Oct 10, 2011 5:19 am
x' = x+1
(x+1)^2 - (x^2)'
= x^2 + 2x + 1 - (x^2 + 1) = 2x
IMO D
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by GmatMathPro » Mon Oct 10, 2011 5:21 am
I don't really know how to type this notation, so let's do it this way...

Treat the definition of "x with a bar" the same way you would treat a function definition. This question would be the same as saying f(x)=x+1. Which of the following is equal to [f(x)]^2-f(x^2).

[f(x)]^2-f(x^2)=

(x+1)^2-(x^2+1)=

x^2+2x+1-x^2-1=

2x

ans: D
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by fcabanski » Mon Oct 10, 2011 10:45 am
The problem is just trying to confuse you by using x bar as the notation for f(x) or y, a function. Whenever there's a strange function notation problem, replace that strange figure with f(x) or y so the notation looks familiar.
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by GMATGuruNY » Mon Oct 10, 2011 8:20 pm
If @x = x+1, which of the following is equal to (@x)² - @(x²) for all values of x?

Let x=3:
(@3)² - @(3²)
= (3+1)² - @9
= 16 - (9+1)
= 6. This is our target.

Now we plug x=3 into the answers to see which yields our target of 6.

Only answer choice D works:
2x = 2*3 = 6.

The correct answer is D.
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by GmatKiss » Tue Oct 11, 2011 11:41 am
Thanks a lot guys :)
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