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zagcollins
- Master | Next Rank: 500 Posts
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5^21*4^11=2*10^n Find value of n
Cant remember the answer options as usual..
this is how i solved it...
5^21*2^11*2^11=2*10^n
Getting 2 in RHS to LHS changes the equation to 5^21*2^10*2^11=10^n
which is nothing but 5^21*2^21=10^n
which can then be rewritten as 10^21=10^n
Cancelling the 10's, n=21.
IS the answer correct and is there a faster method??
Cant remember the answer options as usual..
this is how i solved it...
5^21*2^11*2^11=2*10^n
Getting 2 in RHS to LHS changes the equation to 5^21*2^10*2^11=10^n
which is nothing but 5^21*2^21=10^n
which can then be rewritten as 10^21=10^n
Cancelling the 10's, n=21.
IS the answer correct and is there a faster method??













