Hey guys
Just had a chat with a friend of mine about a GMAT question in his exam. We both weren't quite sure about the way to tackle the following question:
How many pos. odd divisors does 540 have?
First I would factorize it to 3^3 * 2^2 * 5^1 so that the number of all possible divisors is 4*3*2 = 24. Now the "interesting" bit: Since we know that odd*odd = odd and odd*even = even there must not be any divisor of 540 divisible by 2. Does this leave us with 4*3 = 12 possible positive odd divisors for 540?
Thanks a lot, beatthegmat has been awesome so far!
Just had a chat with a friend of mine about a GMAT question in his exam. We both weren't quite sure about the way to tackle the following question:
How many pos. odd divisors does 540 have?
First I would factorize it to 3^3 * 2^2 * 5^1 so that the number of all possible divisors is 4*3*2 = 24. Now the "interesting" bit: Since we know that odd*odd = odd and odd*even = even there must not be any divisor of 540 divisible by 2. Does this leave us with 4*3 = 12 possible positive odd divisors for 540?
Thanks a lot, beatthegmat has been awesome so far!












