if (y+3)(y-1) -(y-2)(y-1)=r(y-1) what is value of y?
1) r^2=25
2) r=5
The[spoiler] OA=E[/spoiler]. I got to OA also. but i have different approach of solving
let given eqn be solved to (y-1)(y+3 -y+2 -r)=0
=> (y-1)(5-r)=0
it says y=1..
so there is no need for any of the statement. Answer should be D
1) r^2=25
2) r=5
The[spoiler] OA=E[/spoiler]. I got to OA also. but i have different approach of solving
let given eqn be solved to (y-1)(y+3 -y+2 -r)=0
=> (y-1)(5-r)=0
it says y=1..
so there is no need for any of the statement. Answer should be D
