I might be slow on this one ...narik11 wrote:It has to be option E:
It says just integers may be positive or negative.
Option 1 works fine for positive integers and for the other scenario it doesn't
Option 2 can be eliminated as discussed in the above posts.
irrespective of m being positive or negative ..... you get a number which has many zeroes and a 1 .... if you now add that to 5 ..... you get a number which has some zeroes , a five and a one ... Rule of divisibility says that the sum of the digits should be divisible by 3... so 5+ 1 + how many ever zeroes is always divisible by 3....
