BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Two trees have a combined height of 60 feet, and the taller

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Moderator
Posts: 2640
Joined: Sun Oct 29, 2017 2:08 pmFollowed by: 2 members
by AAPL » Wed May 29, 2019 4:38 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

Manhattan Prep

Two trees have a combined height of 60 feet, and the taller tree is \(x\) times the height of the shorter tree. How tall is the shorter tree, in term of \(x\)?

A. \(\frac{60}{1+x}\)
B. \(\frac{60}{x}\)
C. \(\frac{30}{x}\)
D. \(60-2x\)
E. \(30-5x\)

OA A
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8151
Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members
Location: Los Angeles, CA
Thanked: 43 times

by Scott@TargetTestPrep » Sat Jun 01, 2019 5:23 am
AAPL wrote:Manhattan Prep

Two trees have a combined height of 60 feet, and the taller tree is \(x\) times the height of the shorter tree. How tall is the shorter tree, in term of \(x\)?

A. \(\frac{60}{1+x}\)
B. \(\frac{60}{x}\)
C. \(\frac{30}{x}\)
D. \(60-2x\)
E. \(30-5x\)

OA A
We can create the equation in which s = the height of the shorter tree, and xs = the height of the taller tree.

s + xs = 60

s(1 + x) = 60

s = 60/(1 + x)

Answer: A

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2214
Joined: Fri Mar 02, 2018 2:22 pmFollowed by: 5 members

by deloitte247 » Fri Jun 07, 2019 1:44 pm
Let the taller tree = T
Let the shorter tree = S
$$T+S=60ft---eqni$$
$$T=x\cdot S---equ\ ii$$
$$substituting\ \left(X\cdot S\right)for\ T\ in\ equ\ i$$
$$\left(x\cdot S\right)+S=60$$
$$xS+S=60$$
$$S\left(x+1\right)=60$$
divide through by coefficient of S
$$\frac{S\left(x+1\right)}{x+1}=\frac{60}{x+1}$$
$$S=\frac{60}{x+1}$$

$$Answer\ is\ Option\ A$$
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1