saadishah wrote:If (a-b)/c < 0, is a > b?
(1) c < 0
(2) a + b < 0
(a-b)/c < 0 requires that (a-b) and c have DIFFERENT SIGNS.
Statement 1: c < 0
Since (a-b) and c must have different signs, (a-b) must be POSITIVE:
a - b > 0
a > b.
SUFFICIENT.
Statement 2: a + b < 0
It's possible that a=-1, b=0 and c=1, in which case a<b.
It's possible that a=0, b=-1 and c=1, in which case a>b.
INSUFFICIENT.
The correct answer is
A.
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