dferm wrote:Jack and Mark both received hourly wage increases of 6 percent. After the wage increases, Jack's hourly wage was how many dollars per hour more than Mark's?
(1) Before the wage increases, Jack's hourly wage was $5.00 per hour more than Mark's.
(2) Before the wage increases, the ratio of Jack's hourly wage to Mark's hourly wage was 4 to 3.
Please help...
Thanks.
let jack's wage=x; mark's wage=y;
1) x=5+y, after hourly increase of 6%, mark's wage would be 1.06y,
and jack's wage would be(5.30+1.06y)
therefore, jack's hourly wage is 5.30$ more than mark;(jack's wage after increase-mark's wage after increase) (5.30+1.06y-1.06y)
hence 1 is sufficient to answer the question
2) here ratio of x/y=4/3; now here for different values of x different results are possible, for example consider x=8,y=6;
therefore jack's salary after hourly increase is (1.06)8=8.48, mark's salary after hourly increase(1.06)6=6.36;
therefore difference= 2.12;
now consider x=12, y=9;
therefore jack's salary after hourly increase is (1.06)12=12.72; marks salary after hourly increase is(1.06)9=9.54
difference= 12.72-9.54=3.18;
as here different results are possible for different values of x and y, hence 2 alone is not sufficient to answer the question.
hence answer should be
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