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A basketball coach will select the members of a five-player team from among 9 players, including John and Peter...

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A basketball coach will select the members of a five-player team from among 9 players, including John and Peter...

by AAPL » Thu Jun 03, 2021 3:23 am

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A basketball coach will select the members of a five-player team from among 9 players, including John and Peter. If the five players are chosen at random, what is the probability that the coach chooses a team that includes both John and Peter?

A. 1/9
B. 1/6
C. 2/9
D. 5/18
E. 1/3

OA D
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Re: A basketball coach will select the members of a five-player team from among 9 players, including John and Peter...

by Brent@GMATPrepNow » Thu Jun 03, 2021 4:59 am
AAPL wrote: ↑
Thu Jun 03, 2021 3:23 am
 Manhattan Prep

A basketball coach will select the members of a five-player team from among 9 players, including John and Peter. If the five players are chosen at random, what is the probability that the coach chooses a team that includes both John and Peter?

A. 1/9
B. 1/6
C. 2/9
D. 5/18
E. 1/3

OA D
P(John and Peter both on the team) = (# of teams that include both John and Peter) / (total # of 5-person teams possible)

a) # of teams that include both John and Peter
- Put John and Peter on the team. This can be accomplished in 1 way
- Select the remaining 3 team-members from the remaining 7 players. Since the order in which we select the 3 players does not matter, we can use combinations. We can select 3 players from 7 players in 7C3 ways (35 ways)
So, the total # of teams that include both John and Peter = (1)(35) = 35

b) total # of 5-person teams
Select 5 team-members from the 9 players. This can be accomplished in 9C5 ways
So, the total # of 5-person teams = 9C5 = 126

Therefore, the probability that the coach chooses a team that includes both John and Pete = 35/126 = 5/18

Answer: D
Brent Hanneson - Creator of GMATPrepNow.com
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