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Is a/b < 1/2 ?

Expert replies
Source: — Data Sufficiency |

by eaakbari » Sun Apr 04, 2010 8:18 pm
IMO E. But the method of picking numbers took way too long. Can someone suggest alternate approach
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by eaakbari » Sun Apr 04, 2010 8:19 pm
eaakbari wrote:IMO E. But the method of picking numbers took way too long. Can someone suggest alternate approach
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by pink_08 » Sun Apr 04, 2010 8:56 pm
Can you post the numbers you tried to rule out C)
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by fibbonnaci » Sun Apr 04, 2010 9:05 pm
from the question: is 2a <b ?

statement 1)
2a+1<b

pick numbers. say a=2
so b>5. say b=6

then 2a < b. check for other numbers such as negative numbers and zero. you will find it satisfiees the statement.
Sufficient.

Statement 2)
2a-2<b

say a=2,
b>2. say b=3

then 2a> b
but if b=6, then 2a< b.

therefore insufficient.

IMO

A
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by pink_08 » Sun Apr 04, 2010 9:38 pm
fibonacci,,
Is a/b < 1/2 ?
from the question: is 2a <b ?

statement 1)
2a+1<b
you cannot multiply the denominator(variable) in an equality without knowing if its +ve or -ve variable
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by fibbonnaci » Sun Apr 04, 2010 11:12 pm
oops sorry i missed that..


we need to answer whether a/b < 0.5

statement 1:
a/(b-1) <1/2

if b is positive, (b-1)<b
if a/(b-1) is less than half then a number with greater denominator b should definitely give less than half(coz the numerators are the same).

you can check by plugging in numbers.
say a=1 and b=4,
a/(b-1) = 1/3 which is less than 1/2.
then a/b= 1/4 which is less than 0.5

Now consider b is negative and a is also negative.
say a= -1 and b= -2
then according to the equation a/(b-1) = 1/3 which is less than 1/2,
but a/b= 1/2 which is equal to half.
Therefore insufficient.

Statement 2:
(a-1)/b <0.5
say a= 2 and b= 3
then 1/3< 1/2 but a/b > 1/2.

lets check another value: a=3 and b=6
2/6 < 1/2 but a/b= 1/2. Thus insufficient.

combining both:
we need to plug in numbers that satisfy both the equations
say a=1 and b=4
then a/b<1/2

similarly say a=-1 and b= -5
then too a/b <1/2.

sufficient.
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by eaakbari » Mon Apr 05, 2010 12:05 am
fibbonnaci wrote:oops sorry i missed that..


we need to answer whether a/b < 0.5

statement 1:
a/(b-1) <1/2

if b is positive, (b-1)<b
if a/(b-1) is less than half then a number with greater denominator b should definitely give less than half(coz the numerators are the same).

you can check by plugging in numbers.
say a=1 and b=4,
a/(b-1) = 1/3 which is less than 1/2.
then a/b= 1/4 which is less than 0.5

Now consider b is negative and a is also negative.
say a= -1 and b= -2
then according to the equation a/(b-1) = 1/3 which is less than 1/2,
but a/b= 1/2 which is equal to half.
Therefore insufficient.

Statement 2:
(a-1)/b <0.5
say a= 2 and b= 3
then 1/3< 1/2 but a/b > 1/2.

lets check another value: a=3 and b=6
2/6 < 1/2 but a/b= 1/2. Thus insufficient.

combining both:
we need to plug in numbers that satisfy both the equations
say a=1 and b=4
then a/b<1/2

similarly say a=-1 and b= -5
then too a/b <1/2.

sufficient.
I realize I did make a mistake with my calculation, C is the correct answer but I still feel this method of plugging is too time-consuming and convoluted or was that just me?
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by jerryragland » Tue Apr 06, 2010 5:23 pm
Guys, correct me if I am wrong

To find is 2a < b?

(1) a/(b - 1) < 1/2

2a < b - 1 ==> 2a + 1 < b ==> so 2a < b -- 1 Sufficient

(2) (a - 1)/b < 1/2

2a - 2 < b ==> but can not say 2a < b -- 2 Not sufficient

Hence a.
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