BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

If x and y are positive integers, what is the greatest commo

Expert replies
by alanforde800Maximus » Tue Oct 25, 2016 9:38 am
If x and y are positive integers, what is the greatest common factor of x and y?
(1) When x is divided by y, the remainder is 1.
(2) x^2 - 2xy + y^2 = 1


Please assist with above problem.
Join the discussion
Source: — Data Sufficiency |

by crackverbal » Wed Oct 26, 2016 10:28 pm
Hi alanforde800maximus,

The question here tests us on the concept of co-primes. Let me first explain the concept of co-primes before moving on to solve the question.

Two integers a and b are said to be co-prime if the only positive integer that divides both of them is 1. That is, the only common positive factor of the two numbers is 1. This is equivalent to their greatest common divisor(factor) being 1.

for e.g. 4 and 5 are co-prime since the only common factor they share is 1. Similarly 4 and 9 are also co-prime to each other. Two even numbers can never be co-prime as they will always share 2 as a factor.

Two consecutive numbers on the number line will always be co-prime. This is a very important result and is exactly what the question here tests us on.

The question here is a value DS where x and y are given to be positive integers.

Statement 1 : When x is divided by y, the remainder is 1 :

Now there are only two possibilities here

1. The numerator x is always 1 and the denominator y can be any positive integer greater than 1 (1/4, 1/5, 1/103.....). Since x = 1 and y is any positive integer greater than 1, the GCD of x and y will always be 1.

2. The numerator x is always one greater than the denominator y, in other words x and y are consecutive positive integers on the number line where x > y (5/4, 7/6, 143/142....). Since x and y are consecutive positive integers they will always have a GCD of 1. Statement 1 is sufficient

Statement 2 : x^2 - 2xy + y^2 = 1 :

Simplifying we get (x - y)^2 = 1 -----> x and y are consecutive positive integers on the number line (x = 3 and y = 2 or x = 5 and y = 6). Here again the GCD of x and y will always be 1. Statement 2 is sufficient.

OA : D

CrackVerbal Academics Team
Join Free 4 part MBA Through GMAT Video Training Series here -
https://gmat.crackverbal.com/mba-throug ... video-2018

Enroll for our GMAT Trial Course here -
https://gmatonline.crackverbal.com/

For more info on GMAT and MBA, follow us on @AskCrackVerbal
Join the discussion

by [email protected] » Thu Oct 27, 2016 11:16 am
Hi alanforde800Maximus,

This DS question can be solved by a combination of TESTing VALUES and doing a bit of Algebra. We're told that X and Y are POSITIVE INTEGERS. We're asked for the Greatest Common Factor (GCF) of X and Y.

1) When X is divided by Y, the remainder is 1.

This Fact tells us that X = Y +1. This piece of information involves a relatively rare math concept - and one that you probably will not see on the GMAT: when dealing with two consecutive, positive integers, the GCF will always be 1 (meaning that NO other integers will divide evenly into both numbers). Even if you don't know that rule though, it's easy enough to prove. Here are some examples:

X=4, Y=3... X is divisible by 1, 2 and 4... Y is divisible by 1 and 3... the GCF is 1
X=5, Y=4... X is divisible by 1 and 5... Y is divisible by 1, 2 and 4... the GCF is 1
X=6, Y=5... X is divisible by 1, 2, 3 and 6... Y is divisible by 1 and 5... the GCF is 1
Etc.
Thus, the answer to the question is ALWAYS 1.
Fact 1 is SUFFICIENT

2) X^2 - 2XY + Y^2 = 1

This quadratic equation can be 'reverse-FOILed' into...

(X - Y)(X - Y) = 1
(X - Y)^2 = 1
(X - Y) = 1 or -1
Since X and Y differ by 1 or -1, and they're both positive integers, we have the same situation that we have in Fact 1 (above).
Fact 2 is SUFFICIENT

Final Answer: D

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion