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Que: According to the data obtained for the last year, $a can buy a ‘b’ number of items....

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by Max@Math Revolution » Wed Feb 03, 2021 10:41 pm

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Que: According to the data obtained for the last year, $a can buy a ‘b’ number of items. If the average cost of each item increased by 30 percent and also 'b' items can be bought this year, then the number of items can be bought with $8a equals

(A) 4.8b
(B) 2.4b
(C) 6.15b
(D) 8b
(E) 5.50b
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Source: — Problem Solving |

Solution: Cost of b items = $a

Since the cost increases by 30%, the new cost of b items = \(\frac{130}{100}\) * $a = $\(\frac{13a}{10}\)

Thus, with a budget of $\(\frac{13a}{10}\), b items can be bought this year. Thus, with the budget of $8q, the numbers of items that can be bought

=> $\(\frac{8ab}{\frac{13a}{10}}\) (Since $\(\frac{13a}{10}\):b = $8a:x, we get x = \(\frac{8ab}{\frac{13a}{10}}\) = 6.15b

Therefore, C is the correct answer.

Answer C
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