Determine the y-intercepts by plugging in x=0:nahid078 wrote:If equation |x/2|+|y/2|=5 encloses a certain region on the coordinate plane, what is the area of this region?
1) 20
2) 50
3) 100
4) 200
5) 400
|0/2| + |y/2| = 5
|y/2| = 5
y = ±10.
Thus, the y-intercepts are (0, 10) and (0, -10).
Determine the x-intercepts by plugging in y=0:
|x/2| + |0/2| = 5
|x/2| = 5
x = ±10.
Thus, the x-intercepts are (-10, 0) and (10, 0).
Link together (-10, 0), (0, 10), (10, 0) and (0, -10).
The following graph is yielded:

The resulting graph is a square with a diagonal of length 20.
For any square with side s, the length of the diagonal = s√2.
Since s√2 = 20, we get:
s = 20/√2
A = s² = (20/√2)² = 400/2 = 200.
The correct answer is D.













