bhumika.k.shah wrote:Whats the question tryna ask ?
whats the explanation

Can anyone tell me please ?

dnt have the book so if u can post the q , wud appreciate it

here you go. the OA is E

rahul.s wrote:here you go. the OA is E

The graph is symmetrical about x=2

so, part of the curve to the left of the line x=2 will be a mirror image of what is there to the right.

Given if x=1 y=1 so, since it is symmetrical about x =2,

y=1 when x =3

Hence E

i didn't understand

I still dint get it

ajith wrote:

rahul.s wrote:here you go. the OA is E

The graph is symmetrical about x=2

so, part of the curve to the left of the line x=2 will be a mirror image of what is there to the right.

Given if x=1 y=1 so, since it is symmetrical about x =2,

y=1 when x =3

Hence E

rahul.s wrote:i didn't understand

x=2 is a vertical line passing through (2,0)
now the graph is symmetrical about that line

so, any original point to left of x=2 will have a reflection on the right hand side

the reflection of the point (1,1) (it is given that the graph passes through (1,1) about the line x=2 is (1+2, 1)

(the x co-ordinate of point (1,1) is at a distance of 1 on left hand side, the reflection should be at a distance of 1 from x=2 on the right hand side hence it will have co-ordinates of (3,1))

Hence since (1,1) is on the graph, (3,1) should also be on the graph

(1/2,2) is on the graph, so will (2+1.5,2)

bhumika.k.shah wrote:I still dint get it

ajith wrote:

rahul.s wrote:here you go. the OA is E

The graph is symmetrical about x=2

so, part of the curve to the left of the line x=2 will be a mirror image of what is there to the right.

Given if x=1 y=1 so, since it is symmetrical about x =2,

y=1 when x =3

Hence E

hint1 the graph is symmetrical at x=2
----> what ever value u are getting for y for a value of x on left side of the x=2 u will get the same value of y for a point which is equidistant as the point on left side at the right side of x

hint 2 the point x=3 lies in first q
so at at x=3 y will have same value as at x=1
which is 1
hence E

Hint: If you are in a jam and don't know what symmetrical @ x=2 means, you can always use the dirty way to guess. I pictured an imaginary line from x=3 to the graph and then perpendicular to the y axis and the closest answer choice was 1. Ofcourse I would be very cautious when using this method but the graph can be assumed to be drawn at scale UNLESS IT SAYS SO.
Hope this helps!!

It helped me to quickly draw this out and plot these points on the graph for a visual representation

bhumika.k.shah wrote:Whats the question tryna ask ?
whats the explanation

Can anyone tell me please ?

As the graph is symmetric about x = 2, which also represents a parabola (could be new to some) with its vertex on (2, 0); the points equidistant on either side of 2 on x-axis would have the same ordinate. Since 3 is as far from 2 as is 1 on x-axis, both would have the same ordinate on curve.

[spoiler]E[/spoiler]