Length of perpendicular or distance of a point (p, q) from a line a x + b y + c = 0 is
∣a p + b q + c∣ / √(p^2+ q^2)
If (k, 4 - k) is a point on the line x + y = 4 that lie at a unit distance from the line 4 x + 3 y = 10, then
∣4 k + 12 - 3 k - 10∣ / √[4^2 + (4 - k)^2] = 1
∣k + 2∣ = √[k^2 - 8 k + 32]
squaring both sides and solving
k = 7/3.
Hence, the unique point must be (7/3, 5/3).
My protest! If there were two such points on the line, we should have got two distinct values of k here.
How about [spoiler]A[/spoiler]?
lie at a unit
- sanju09
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Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
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Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
- harshavardhanc
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sanju09 wrote:
∣4 k + 12 - 3 k - 10∣ / √[4^2 + (4 - k)^2] = 1
Check the denominator once again.
Shouldn't it be K^2 + (4 - K )^2 ?
You will get 2 values.
Regards,
Harsha
Harsha
- sanju09
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Are you sure that it's without a square root sign? Check it once!harshavardhanc wrote:sanju09 wrote:
∣4 k + 12 - 3 k - 10∣ / √[4^2 + (4 - k)^2] = 1
Check the denominator once again.
Shouldn't it be K^2 + (4 - K )^2 ?
You will get 2 values.
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
- harshavardhanc
- Legendary Member
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Buddy, it's with the square root. But, that's not what I wanted to point out.sanju09 wrote:Are you sure that it's without a square root sign? Check it once!harshavardhanc wrote:sanju09 wrote:
∣4 k + 12 - 3 k - 10∣ / √[4^2 + (4 - k)^2] = 1
Check the denominator once again.
Shouldn't it be K^2 + (4 - K )^2 ?
You will get 2 values.
The point that I wanted you to notice was that in your original equation/formula, you haven mistakenly taken incorrect values for p & q.
Whereas, p should be K, you have taken it as 4. That's why in solving, you didn't get a quadratic equation.
Regards,
Harsha
Harsha
- sanju09
- GMAT Instructor
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oh yeahharshavardhanc wrote:Buddy, it's with the square root. But, that's not what I wanted to point out.sanju09 wrote:Are you sure that it's without a square root sign? Check it once!harshavardhanc wrote:sanju09 wrote:
∣4 k + 12 - 3 k - 10∣ / √[4^2 + (4 - k)^2] = 1
Check the denominator once again.
Shouldn't it be K^2 + (4 - K )^2 ?
You will get 2 values.
The point that I wanted you to notice was that in your original equation/formula, you haven mistakenly taken incorrect values for p & q.
Whereas, p should be K, you have taken it as 4. That's why in solving, you didn't get a quadratic equation.
now you can rock, because the OA is [spoiler]B[/spoiler]
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com












