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Dealing with Remainders

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Dealing with Remainders

by jjayhart » Wed Sep 25, 2013 4:08 pm
I struggle with this sort of problem and the explanation from the OG was less than helpful. What's the best way to approach this?

When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.12, what is the value of y?

(a) 96
(b) 75
(c) 48
(d) 25
(e) 12

Thanks,

Jeremy
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by mevicks » Thu Sep 26, 2013 1:39 am
Note for remainder problems:

x = q*y + r

x => Dividend or Multiple
q => Quotient
y => Divisor or Factor
r => Remainder ( 0<= r < q )
All the numbers in the equation above are integers.

If x is divisible by y then the remainder r is 0.


Solution to the problem:

We know that x is not divisible y because we have a remainder of 9. Lets set up the remainder equation:

x = n.y + r
x = n.y + 9
(x/y) = n + (9/y) ..... (1) Dividing both sides by integer y

But its given that,
(x/y) = 96.12
(x/y) = 96 + 0.12 ..... (2) Splitting into integer and decimal parts

Now, Comparing (1), (2)
(9/y) = 0.12
Thus y = (9/0.12) = 75

[spoiler]Correct Answer : B[/spoiler]
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by theCodeToGMAT » Thu Sep 26, 2013 2:01 am
.12y = 9

y = 75

Answer [spoiler]{B}[/spoiler]
R A H U L
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