Let k=10.AAPL wrote:Magoosh
2k years ago Frank was 3k years old. In k years Frank's age, in years, will be
A. 4k
B. 5k
C. 6k
D. 7k
E. 8k
2k years ago Frank was 3k years old.
Since k=10, 20 years ago Frank was 30 years old, implying that his age now = 30+20 = 50.
In k years Frank's age, in years, will be:
Since Frank is now 50 years old, Frank's age in 10 years = 50+10 = 60.
The correct answer must yield a value of 60 when k=10.
Only C works:
6k = 6*10 = 60.
The correct answer is C.
