vladmire wrote:How can I find the equation of the line that contains the point (−1, 3) and which is perpendicular to the line with the equation y + 2x+ 1 = 0.
Is the answer to this y=1/2x + 7/2
Second question (y^10/125y^-5)^-2/3
Eq of line = y =mx+c
where m is slope
so, from given eq. y = -2x-1
Slope = -2
Now, If 2 lines are perpendicular, product of their slope = -1
Let m1 b the slope of 2nd line
then m1* -2 = -1
m1 =1/2
Now, Eq of line
y =mx+c
(-1,3) is given'
3 = -1/2+C
c = 3+1/2
c =7/2
So, y = 1/2x+7/2should be the ans IMO
