800guy wrote:i'll post OA when a few people have responded..
What is the least possible distance between a point on the circle x^2 + y^2 = 1 and a point on the line y = 3/4*x - 3?
A) 1.4
B) sqrt (2)
C) 1.7
D) sqrt (3)
E) 2.0
also got 1.4
it is easy to draw circle with R=1, and center with the origin
then construct line y=3/4(x)-3
it intersect line x in point (4,0) and line y in point (0,-3)
and forms triangle with sides x,y-lines and y=3/4*x-3
now let us drop perpendicular on the base of triangle from the origin
it will be the height of triangle
the height of triangle-radius of circle is out target
to find the height of triangle different way exist, i solved using area of triangle
Area -1/2*3*4=6
and one more way to find =1/2*base* height
base^2=3^2+4^2=5
area=1/2*5*height
6=1/2*5*h
h=12/5
and r=1
12/5-1=7/5=1/4
hope it makes sence
