3x -( 2y + 2z) = 32 and (3x) ^ 1/2 - (2y + 2z) ^ 1/2 = 4 => (3x) ^ 1/2 + (2y + 2z) ^ 1/2 = 8abhi332 wrote:If 3x - 2y - z = 32 + z and (3x) ^ 1/2 - (2y + 2z) ^ 1/2 = 4 , what is the value of x + y + z ?
(A) 3
(B) 9
(C) 10
(D) 12
(E) 14
(3x) ^ 1/2 =6
3x = 36
x=12
2y+2z =4
y+z = 2
[spoiler]x+y+z =14[/spoiler]












