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have bug collections

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by sanju09 » Sat Jul 10, 2010 5:55 am
Anthony and Carolyn have bug collections. If they combined their collections, they would have a collection of twenty bugs. Which of the following statements could not be true?
(A) Carolyn has a dozen bugs.
(B) Anthony has eleven bugs.
(C) Anthony has one more bug than Carolyn.
(D) Carolyn has two more bugs than Anthony.
(E) Carolyn has one bug.
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by grockit_andrea » Sat Jul 10, 2010 6:07 am
A, B, and E can all be eliminated pretty quickly: if Carolyn had 12, Anthony could have 8; if Anthony had 11, Carolyn could have 9; if Carolyn had 1, Anthony could have 19. Looking at those numbers, we can also eliminate choice D; by switching the names, we see that Carolyn could have 11 and Anthony could have 9. 11 is 2 more than 9, so D is possible. That just leaves C. If Anthony had one more bug than Carolyn, one of them would have an odd number of bugs and one would have an even number. An odd + an even equals an odd number, and 20 is even, so this is impossible. Choice C could not happen, and therefore is the correct answer.
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by kvcpk » Sat Jul 10, 2010 6:09 am
Totally Stumped. Answering logically.. llike CR.

Since Question says both A and C have bug collections, E could not be true.

What is OA?
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by kvcpk » Sat Jul 10, 2010 6:11 am
Oops.. Thought them to be software Bugs.. Thought they could even have same bugs...
Too much thinking... lol
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by outreach » Sat Jul 10, 2010 11:15 am
both can have odd number of bugs?
grockit_andrea wrote:A, B, and E can all be eliminated pretty quickly: if Carolyn had 12, Anthony could have 8; if Anthony had 11, Carolyn could have 9; if Carolyn had 1, Anthony could have 19. Looking at those numbers, we can also eliminate choice D; by switching the names, we see that Carolyn could have 11 and Anthony could have 9. 11 is 2 more than 9, so D is possible. That just leaves C. If Anthony had one more bug than Carolyn, one of them would have an odd number of bugs and one would have an even number. An odd + an even equals an odd number, and 20 is even, so this is impossible. Choice C could not happen, and therefore is the correct answer.
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by gmatmachoman » Sun Jul 11, 2010 12:53 am
kvcpk wrote:Oops.. Thought them to be software Bugs.. Thought they could even have same bugs...
Too much thinking... lol
Praveen...

ateast u r far better than me..I am reading CR questions like SC..and look for SV agreement ..and then after 20 secs realise that that's a CR one..
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by kvcpk » Sun Jul 11, 2010 12:59 am
gmatmachoman wrote:
kvcpk wrote:Oops.. Thought them to be software Bugs.. Thought they could even have same bugs...
Too much thinking... lol
Praveen...

ateast u r far better than me..I am reading CR questions like SC..and look for SV agreement ..and then after 20 secs realise that that's a CR one..
HaHa.. Probably you need some break :)
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