Number Properties - Seems easy, but just can't figure!

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Folks, please explain the steps you take to solve this:

If a < -1, is b between 0 and 1 ?

1. -b < -a
2. -1 < ab < 0

  • (A) if statement (1) BY ITSELF is sufficient to answer the question, but statement (2) by itself is not;

    (B) if statement (2) BY ITSELF is sufficient to answer the question, but statement (1) by itself is not;

    (C) if statements (1) and (2) TAKEN TOGETHER are sufficient to answer the question, even though NEITHER statement BY ITSELF is sufficient;

    (D) if EITHER statement BY ITSELF is sufficient to answer the question;

    (E) if statements (1) and (2) TAKEN TOGETHER are NOT sufficient to answer the question, requiring more data pertaining to the problem.
This question just killed me during practice, I just couldn't figure. :(
Source: — Data Sufficiency |

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by Rahul@gurome » Fri Oct 22, 2010 9:18 pm
clawhammer wrote:Folks, please explain the steps you take to solve this:

If a < -1, is b between 0 and 1 ?

1. -b < -a
2. -1 < ab < 0

...This question just killed me during practice, I just couldn't figure. :(

Given : a < -1 => a is negative and less than -1.

Statement 1: -b < -a => a < b
(Multiplication/division with -1 changes the inequality sign. Take -2 and -3 for example. -3 < -2 but 3 > 2.)

=> a < b
=> b is greater than -1.
We can't say whether b is between 0 and 1. Not Sufficient.

Statement 2: -1 < ab < 0 => ab is a negative fraction.

Now as a is negative, ab will only be negative when b is positive => b > 0.
Again a is less than -1,
(i) ab < -1 if b > 1
(ii) ab > -1 if b < 1

Statement 2 gives that ab > -1 => b < 1.

Therefore, b is between 0 and 1.

The correct answer is B.
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by Rezinka » Fri Oct 22, 2010 9:31 pm
The question says :
a < -1
or, a is any negative number less than -1

Statement 1 :
-b < -a
or, b > a (multiplying both sides by negative changes the inequality sign)
so, b can be any number greater than -1................. NOT SUFFICIENT

Statement 2 :
-1 < ab < 0
ab is negative fraction.
Since a < -1 so b has to be between 0 and 1 to give a negave fraction........ SUFFICIENT

Ans : B

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by Geva@EconomistGMAT » Sun Oct 24, 2010 4:14 am
Rezinka wrote:The question says :
a < -1
or, a is any negative number less than -1


Statement 2 :
-1 < ab < 0
ab is negative fraction.
Since a < -1 so b has to be between 0 and 1 to give a negave fraction........ SUFFICIENT

Ans : B
Great method. If you can't see why b has to a fraction for ab to be a negative fraction, use the same principle of flipping the sign when multiplying/dividing by a negative value. Since you know that a is definitely negative, you can turn -1<ab into
-1/a > b (divide by a to isolate b, flip the sign because of div by negative).

since a is negative, the fraction -1/a is positive, and since a is smaller than -1 (e.g. -2, -3, -4), -1/a must be a positive FRACTION (1/2, 1/3, 1/4, respectively). b must therefore be smaller than a fraction byt still positive, leaving b as a number between 0 and 1.
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by neerajkumar1_1 » Sun Oct 24, 2010 5:22 am
another way to look at it...

ofcourse by now u agree that statement 1 is insufficient..
so i will just concentrate on statement 2...

-1<ab<0

we already know that a<-1 and negative...

so we can divide the equation -1<ab<0 by a and keeping in mind that a is -ve...

1/a > b > 0 ... ( flip the sign because a is -ve and the negative sign is removed )

now 1/a will always be a fraction < 1 since a's absolute value is always > 1
so b will be less than 1 and greater than 0...