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The table above shows the numbers of hours of television programs that Jane recorded last week and the numbers of...

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by BTGmoderatorLU » Tue Dec 29, 2020 6:07 am

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2020-04-20_2147.png
The table above shows the number of hours of television programs that Jane recorded last week and the number of hours she spent viewing these recorded programs. No recorded program was viewed more than once. If h is the number of hours of recorded programs she had not yet viewed by the end of Friday, which of the following intervals represents all of the possible values of h?

A. \(0 \leq h \leq 1\)
B. \(1 \leq h \leq 2\)
C. \(2 \leq h \leq 3\)
D. \(0 \leq h \leq 2\)
E. \(1 \leq h \leq 3\)

The OA is E
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Re: The table above shows the numbers of hours of television programs that Jane recorded last week and the numbers of...

by Scott@TargetTestPrep » Fri Jan 01, 2021 5:02 am
BTGmoderatorLU wrote: ↑
Tue Dec 29, 2020 6:07 am
 Source: Official Guide

2020-04-20_2147.png

The table above shows the number of hours of television programs that Jane recorded last week and the number of hours she spent viewing these recorded programs. No recorded program was viewed more than once. If h is the number of hours of recorded programs she had not yet viewed by the end of Friday, which of the following intervals represents all of the possible values of h?

A. \(0 \leq h \leq 1\)
B. \(1 \leq h \leq 2\)
C. \(2 \leq h \leq 3\)
D. \(0 \leq h \leq 2\)
E. \(1 \leq h \leq 3\)

The OA is E
Solution:

The total recording time is 4 + 2 = 6 hours. The total viewing time is between 1 + 2 = 3 hours and 2 + 3 = 5 hours. Therefore, the number of hours of recorded programs Jane had not yet viewed by the end of Friday is between 6 - 5 = 1 hour and 6 - 3 = 3 hours. That is, 1 ≤ h ≤ 3.

Answer: E

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