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Are x and y both positive ?

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Source: — Data Sufficiency |

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by Brent@GMATPrepNow » Fri Jan 23, 2015 4:58 pm
utkalnayak wrote:Are x and y both positive ?
1. 2x - 2y = 1
2. x/y > 1

OA: C
Target question: Are x and y both positive?

Statement 1: 2x - 2y = 1
There are several pairs of numbers that satisfy this condition. Here are two:
Case a: x = 1 and y = 0.5, in which case x and y are both positive
Case b: x = -0.5 and y = -1, in which case x and y are not both positive
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: x/y > 1
This tells us that x/y is positive. This means that either x and y are both positive or x and y are both negative. Here are two possible cases:
Case a: x = 4 and y = 2, in which case x and y are both positive
Case b: x = -4 and y = -2, in which case x and y are not both positive
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2
Statement 1 tells us that 2x - 2y = 1.
Divide both sides by 2 to get: x - y = 1/2
Solve for x to get x = y + 1/2

Now take the statement 2 inequality (x/y > 1) and replace x with y + 1/2 to get:
(y + 1/2)/y > 1
Rewrite as: y/y + (1/2)/y > 1
Simplify: 1 + 1/(2y) > 1
Subtract 1 from both sides: 1/(2y) > 0
If 1/(2y) is positive, then y must be positive.

Statement 2 tells us that either x and y are both positive or x and y are both negative.
Now that we know that y is positive, it must be the case that x and y are both positive
Since we can now answer the target question with certainty, the combined statements are SUFFICIENT

Answer = C

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by Matt@VeritasPrep » Sun Jan 25, 2015 8:19 pm
S1::
x - y = 1/2
x = y + 1/2

We could have x = 1, y = 1/2 ... or x = -1 and y = -3/2, so this is NOT sufficient. (Conceptually, we could just say that x > y, but we don't know anything about its sign.)

S2::
x/y > 1

We want to multiply both sides by y, but we need to know its sign first. We have two possibilities: y > 0 and 0 > y. If y > 0, then x > y. If y < 0, then x < y. So either x and y are BOTH positive or x and y are BOTH negative; this is also NOT sufficient.

Taking the two together, we know from S1 that x = y + 1/2, or x > y. S2 told us that if x > y, then x and y are both positive. (The only other possibility from S2 is that 0 > y > x, but that doesn't agree with S1, so it can't be the case.) Taking the two together, we're set: x and y are both positive.
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by towerSpider » Mon Feb 16, 2015 7:01 am
utkalnayak wrote:Are x and y both positive ?
1. 2x - 2y = 1
2. x/y > 1

OA: C
1. 2(x-y) = 1 => x-y = 1/2 => x is .5 greater than y =>
case 1: both could be positing: y = 1, x = 1.5
case 2: both could be negative: y = -3, x = -2.5
case 3: x +ve, and y -ve: y = -.1, x = .4

both could be positing or not, so 1. IS NOT ENOUGH.

2. it means that x>y AND both are EITHER +ve, OR -ve:
...NOT ENOUGH

combine together. 2. helps to eliminate case 3. it also helps to eliminate case 2, -2.5/-3<1. so we remain with case 1 ONLY:

Ans. C[/u][/b]
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by Jeff@TargetTestPrep » Thu Apr 09, 2015 1:33 pm
utkalnayak wrote:Are x and y both positive ?
1. 2x - 2y = 1
2. x/y > 1

OA: C
Solution:

We are not provided any given information in the question stem, so we can immediately move to the analysis of the two statements.

Statement One Alone:

1) 2x - 2y = 1

The first thing we should do here is to simplify statement one.

2(x - y) = 1

x - y = ½

We can clearly see that x and y can both be positive to yield ½ as their difference (for example, x could be 1.5 and y could be 1)

OR

x and y could both be negative (for example, x could be -1 and y could be -1.5)

OR

x could be positive and y could be negative (for example, x could be ¼ and y could be -¼)

Thus, statement one is insufficient.

Statement Two Alone:

2) x/y > 1

Statement two does not provide enough information to determine whether x and y are either both positive or both negative. Remember that if something is > 1, that something is positive. Also, remember that negative divided by negative is positive, and positive divided by positive is also positive. We can't get anywhere with statement two alone.

Statements One and Two Together:

It's important to be cognizant of situations in which we are provided an inequality and an equation with the same two variables. In these situations, can substitute the equation into the inequality. Doing so will allow us to simplify the inequality. In this case we need to first simplify our equation from statement one:

x - y = ½

x = ½ + y

Now we can substitute ½ + y for x into the inequality x/y > 1. Thus, we have:

(½ + y)/y > 1

½/y + y/y > 1

½/y + 1 > 1

½/y > 0

Because ½/y is greater than zero, y MUST also be greater than zero. Lastly, because we know that x = ½ + y, it follows that x MUST also be greater than zero. Thus, both x and y are positive.

The answer is C

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by josjots » Wed Sep 07, 2016 4:44 am
Using coordinate geometry:

Statement 2: x/y>1 or x>y is represented by area below the line y=x on the graph.
Statement 1: Line equation- y=x-0.5 represented by a line with slope 1 and y coordinate -0.5.

Even combining 1&2, since the line is already in the region represented by Statement 1, we can not determine the answer to the target question. The solution can lie on the line represented by Statement 2.

Where am I going wrong. Help please..
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by [email protected] » Wed Sep 07, 2016 7:38 am
Hi josjots,

You have to be careful about manipulating inequalities.

In Fact 2, we're told that X/Y > 1.

IF... X and Y are both POSITIVE, then X > Y
IF... X and Y are both NEGATIVE, then X < Y

Thinking in those terms, what would you do differently?

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