5 litres of water is added to a certain quantity of pure milk costing $3 per litre. If, by selling the mixture at the same price as before a profit of 20% is made, what is the amount of pure milk in the mixture?
My approach:
Quantity of milk = x lts
Cost of milk per lt = $3
Water added = 5 lt
Total quantity of mix = x+5 lts
Selling Price of milk = 3x
Mixture (x+5) lts is also sold at $3 per lt. Therefore SP of mixture = 3(x+5)
I am stuck after this. How do i set up the 20% profit?
Help needed.
Thank you
My approach:
Quantity of milk = x lts
Cost of milk per lt = $3
Water added = 5 lt
Total quantity of mix = x+5 lts
Selling Price of milk = 3x
Mixture (x+5) lts is also sold at $3 per lt. Therefore SP of mixture = 3(x+5)
I am stuck after this. How do i set up the 20% profit?
Help needed.
Thank you












