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Number Systems

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Number Systems

by sukhman » Sat Oct 12, 2013 6:49 am
Find the number of consecutive zeros at the end of the following numbers.

100!+ 200!

a.73 b.24 c.11 d.22


100!*200!

a.49 b.73 c.132 d.33
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by theCodeToGMAT » Sat Oct 12, 2013 7:29 am
100! --> 20 + 4 = 24
200! --> 40 + 8 + 1 = 49

Q1.Since, adding 100! will impact 200!... so, 24

Q2.Since, Multiplying.. we will add 24+49 = 73
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