Good one

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Good one

by boros2203 » Sat Aug 07, 2010 8:58 am
If y > 0, what is the value of x?
1. |x - 3| > y
2. |x - 3| < - y

Please provide relevant explanations....

Answer after discussion[/spoiler]
Source: — Data Sufficiency |

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by outreach » Sat Aug 07, 2010 9:16 am
https://www.manhattangmat.com/forums/if- ... t2675.html
boros2203 wrote:If y > 0, what is the value of x?
1. |x - 3| > y
2. |x - 3| < - y

Please provide relevant explanations....

Answer after discussion[/spoiler]
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by gmatmachoman » Sat Aug 07, 2010 10:27 am
boros2203 wrote:If y > 0, what is the value of x?
1. |x - 3| > y
2. |x - 3| < - y

Please provide relevant explanations....

Answer after discussion[/spoiler]
In st 2 :

LHS is always +ve. But we know that Y is also positive. Putting the values together in the equation , its violating the stated conditions:

+ < - ( +)
This is a Impossible condition. Plzz chk the question stem

Anyways st1 is of less use.. chk st2 : is that rightly transcribed?

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by selango » Sat Aug 07, 2010 10:39 am
Yes I also had doubt in this..

It should be y>=0

|x - 3| <= - y

In this case |x-3|=0

x=3

Am I right?
--Anand--

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by boros2203 » Sun Aug 08, 2010 7:06 am
sorry for missing the = symbol .It is y>=0