Jinglander wrote:Hey guys sorry I dont have an answer for this
A jury of 12 is to be selected from a pool of 15. 2/3 are male 1/3 are female. What is the probability that the selected jury will be 2/3 male
Here's another way to approach the question:
A jury of 12 members is to be selected, in which 2/3 of the members should be male.
Now 2/3 of 12 = 2*4 = 8. So, the male members can be 8, 9 or 10.
If there are 8 males, then females = 4
If there are 9 males, then females = 3
If there are 10 males, then females = 2
So, No. of favorable possibilities = 10C8 * 5C4 + 10C9 * 5C3 + 10C10 * 5C2 = 45*5 + 10*10 + 1*10 = 225 + 100 + 10 = 335
Total no. of possibilities = 15C12 = 455
So, required probability = 335/455 =
67/91
Does that help?
Rahul Lakhani
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