- sumit.sinha
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PS Question # 2 - Siblings
Source: Beat The GMAT — Problem Solving |
A is the answer
Saurabh Goyal
[email protected]
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EveryBody Wants to Win But Nobody wants to prepare for Win.
[email protected]
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EveryBody Wants to Win But Nobody wants to prepare for Win.
Basic principle of both the question is same. (Incidentally the answer is same too!
)
I'll explain the first one.
Number of possible ways to select two students such that one of them is a junior student and another is a senior student = (Number of possible ways to select a junior student out of 1000)*(Number of possible ways to select a senior student out of 800) = 1000*800
Number of possible ways to select a sibling pair = (Number of possible ways to select one of them out of 60)*(Number of possible ways to select other one of them out of 60) = 60*1
(Number of possible ways to select other one of them out of 60 is 1 because as the first one is already selected other one is fixed for him/her.)
Therefore required probability = 60/(800*1000) = 3/40,000
The correct answer is A.
I'll explain the first one.
Number of possible ways to select two students such that one of them is a junior student and another is a senior student = (Number of possible ways to select a junior student out of 1000)*(Number of possible ways to select a senior student out of 800) = 1000*800
Number of possible ways to select a sibling pair = (Number of possible ways to select one of them out of 60)*(Number of possible ways to select other one of them out of 60) = 60*1
(Number of possible ways to select other one of them out of 60 is 1 because as the first one is already selected other one is fixed for him/her.)
Therefore required probability = 60/(800*1000) = 3/40,000
The correct answer is A.
Rahul Lakhani
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Gurome, Inc.
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On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
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Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Thanks for the explanation Rahul.Rahul@gurome wrote:Basic principle of both the question is same. (Incidentally the answer is same too!)
I'll explain the first one.
Number of possible ways to select two students such that one of them is a junior student and another is a senior student = (Number of possible ways to select a junior student out of 1000)*(Number of possible ways to select a senior student out of 800) = 1000*800
Number of possible ways to select a sibling pair = (Number of possible ways to select one of them out of 60)*(Number of possible ways to select other one of them out of 60) = 60*1
(Number of possible ways to select other one of them out of 60 is 1 because as the first one is already selected other one is fixed for him/her.)
Therefore required probability = 60/(800*1000) = 3/40,000
The correct answer is A.
But dont i need to take into consideration the way/sequence in which i select the siblings??
i.e in one sequence- i first select a sibling form Junior class and then select the matching one from senior class.
and in the 2nd sequence- i first select a sibling form senior class and then select the matching one from junior class
Cheers,
Sumit
Sumit















